24h^2-56h-48=0

Solution for 24h^2-56h-48=0 equation:

24h^2-56h-48=0

a = 24; b = -56; c = -48;
Δ = b2-4ac
Δ = -562-4·24·(-48)
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7744}=88$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-88}{2*24}=\frac{-32}{48}
=-2/3
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+88}{2*24}=\frac{144}{48}
=3
$